Задача 2
Приведем задачу у виду удобному для решения
Заполним симплекс – таблицу
Таблица 4.3
№ | Базис | С | План | 3 | 2 | 5 | 0 | 0 | 0 | 0 | 0 | 0 | М | М | М |
I | М | 2000 | 50 | 20 | <180> | -1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | |
М | 120 | 6 | 4 | 3 | 0 | -1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | ||
М | 40 | 2 | 1 | 1 | 0 | 0 | -1 | 0 | 0 | 0 | 0 | 0 | 1 | ||
0 | 12 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | ||
0 | 20 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | ||
0 | 16 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | ||
0 | -3 | -2 | -5 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | |||
М | 2160 | 58 | 24 | 184 | -1 | -1 | -1 | 0 | 0 | 0 | 0 | 0 | 0 | ||
II | 5 | 11.11 | 0.28 | 0.11 | 1 | -0.006 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | ||
М | 86.67 | 5.17 | 3.67 | 0 | 0.017 | -1 | 0 | 0 | 0 | 0 | 1 | 0 | |||
М | 28.89 | 1.72 | 0.89 | 0 | 0.006 | 0 | -1 | 0 | 0 | 0 | 0 | 1 | |||
0 | 12 | <1> | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | |||
0 | 20 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | |||
0 | 16 | -0.28 | -0.11 | 0 | 0.006 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | |||
55.55 | -1.6 | -1.45 | 0 | -0.03 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | ||||
М | 115.56 | 6.89 | 4.56 | 0 | 0.023 | -1 | -1 | 0 | 0 | 0 | 0 | 0 | |||
№ | Базис | С | План | 3 | 2 | 5 | 0 | 0 | 0 | 0 | 0 | 0 | М | М | М |
III | 5 | 7.78 | 0 | 0.11 | 1 | -0.006 | 0 | 0 | -0.28 | 0 | 0 | 0 | 0 | ||
М | 24.67 | 0 | <3.67> | 0 | 0.017 | -1 | 0 | -5.17 | 0 | 0 | 1 | 0 | |||
М | 8.22 | 0 | 0.89 | 0 | 0.006 | 0 | -1 | -1.72 | 0 | 0 | 0 | 1 | |||
3 | 12 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | |||
0 | 20 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | |||
0 | 18.22 | 0 | -0.11 | 0 | 0.006 | 0 | 0 | 0.28 | 0 | 1 | 0 | 0 | |||
74.9 | 0 | -1.45 | 0 | -0.03 | 0 | 0 | -1.4 | 0 | 0 | 0 | 0 | ||||
М | 32.89 | 0 | 4.56 | 0 | 0.023 | -1 | -1 | -6.89 | 0 | 0 | 0 | 0 | |||
IV | 5 | 7.03 | 0 | 0 | 1 | -0.006 | 0.03 | 0 | -0.12 | 0 | 0 | 0 | |||
2 | 6.73 | 0 | 1 | 0 | 0.004 | -0.27 | 0 | -1.4 | 0 | 0 | 0 | ||||
М | 2.24 | 0 | 0 | 0 | 0.002 | <0.24> | -1 | -0.47 | 0 | 0 | 1 | ||||
3 | 12 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | ||||
0 | 13.27 | 0 | 0 | 0 | -0.004 | 0.27 | 0 | 1.4 | 1 | 0 | 0 | ||||
0 | 8.97 | 0 | 0 | 0 | 0.006 | -0.03 | 0 | 0.12 | 0 | 1 | 0 | ||||
84.61 | 0 | 0 | 0 | -0.02 | -0.39 | 0 | -3.4 | 0 | 0 | 0 | |||||
М | 2.24 | 0 | 0 | 0 | 0.002 | 0.24 | -1 | -0.47 | 0 | 0 | 0 | ||||
V | 5 | 6.75 | 0 | 0 | 1 | -0.006 | 0 | 0.12 | -0.062 | 0 | 0 | ||||
2 | 9.25 | 0 | 1 | 0 | 0.006 | 0 | -1.12 | -1.94 | 0 | 0 | |||||
0 | 9.25 | 0 | 0 | 0 | 0.006 | 1 | -4.12 | -1.94 | 0 | 0 | |||||
3 | 12 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | |||||
0 | 10.75 | 0 | 0 | 0 | -0.006 | 0 | 1.12 | 1.94 | 1 | 0 | |||||
0 | 9.25 | 0 | 0 | 0 | 0.006 | 0 | -0.12 | 0.062 | 0 | 1 | |||||
88.25 | 0 | 0 | 0 | -1.019 | 0 | -1.62 | -1.19 | 0 | 0 |
Учитывая предельные нормы суточной выдачи оптимальный рацион для скота будет включать в себя корма: сено – 12, силос – 9.25, концентраты – 6.25. При чем остаются недоиспользованные ресурсы по силосу в размере 10.75 и по концентратам – 9.25. В этом случае стоимость рациона составила 88.25 копеек.